因为我返回给前端的不是json字符串,而是序列化后的java对象或者数组,所以网上的那种jackjson和fastjson进行转换的方法没效,于是我换了一下方法,话不多说,show code:

@Configuration
public class JsonConfig {
    @Bean
    @Primary
    @ConditionalOnMissingBean(ObjectMapper.class)
    public ObjectMapper jacksonObjectMapper(Jackson2ObjectMapperBuilder builder)
    {
        ObjectMapper objectMapper = builder.createXmlMapper(false).build();

        // 通过该方法对mapper对象进行设置,所有序列化的对象都将按改规则进行系列化
        // Include.Include.ALWAYS 默认
        // Include.NON_DEFAULT 属性为默认值不序列化
        // Include.NON_EMPTY 属性为 空("") 或者为 NULL 都不序列化,则返回的json是没有这个字段的。这样对移动端会更省流量
        // Include.NON_NULL 属性为NULL 不序列化,就是为null的字段不参加序列化
        //objectMapper.setSerializationInclusion(Include.NON_EMPTY);
        // 字段保留,将null值转为""
        objectMapper.getSerializerProvider().setNullValueSerializer(new JsonSerializer<Object>()
        {
            @Override
            public void serialize(Object o, JsonGenerator jsonGenerator,
                                  SerializerProvider serializerProvider)
                    throws IOException, JsonProcessingException
            {
                jsonGenerator.writeString("");
            }
        });
        return objectMapper;
    }
}
Last modification:July 6, 2021
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